慕桂英4014372
您可以groupby按自定义使用Series:df = pd.DataFrame({'a': [1, 1, -1, 1, -1, -1]})print (df) a0 11 12 -13 14 -15 -1print ((df.a != df.a.shift()).cumsum())0 11 12 23 34 45 4Name: a, dtype: int32for i, g in df.groupby([(df.a != df.a.shift()).cumsum()]): print (i) print (g) print (g.a.tolist()) a0 11 1[1, 1]2 a2 -1[-1]3 a3 1[1]4 a4 -15 -1[-1, -1]