求大佬帮忙，老师今天讲的太快，没懂，作业不会做

Question

已知数据手机号数组：

String[] phones = {"13804010040","13804010041","13804010042",

"13804010043","13804010044","13804010045",

"13804010046","13804010047","13804010044",

"13804010054","13804010055","13804010056",

"13804010058","13804010059","13804010060",

"13804010061","13804010062","13804010063",

"13804010064","13804010065","13804010066",

"13804010067","13804010068","13804010069",

"13804010070","13804010071","13804010072",

"13804010073","13804010074","13804010075",

"13804010045","13804010057","13804010063",

"13804010058","13804010069","13804010066"}

1. 1使用集合，快速去除重复的手机号，将去重后手机号存

放的List集合中，输出去重后有多少个手机号，13804010099这个手机号是否存在

 

1. 2已知上面手机号数组，将数组转为集合，然后使用map集合存储每个手机号出现的次数，并遍历输出

Answer 1

做个遍历，在遍历的函数之外放一个全局变量。遍历到了就改遍历函数外的全局变量。这是学习算法的，还是要靠自己的逻辑去实现。