蓝山帝景
首先，创建一个MySQL表来存储图像，例如：create table testblob (
image_id tinyint(3) not null default '0',
image_type varchar(25) not null default '',
image blob not null,
image_size varchar(25) not null default '',
image_ctgy varchar(25) not null default '',
image_name varchar(50) not null default '');然后，您可以将图像写入数据库，如下所示：/***
* All of the below MySQL_ commands can be easily
* translated to MySQLi_ with the additions as commented
***/ $imgData = file_get_contents($filename);$size = getimagesize($filename);mysql_connect("localhost", "$username", "$password");mysql_select_db ("$dbname");// mysqli // $link = mysqli_connect("localhost", $username, $password,$dbname); $sql = sprintf("INSERT INTO testblob
(image_type, image, image_size, image_name)
VALUES
('%s', '%s', '%d', '%s')",
/***
* For all mysqli_ functions below, the syntax is:
* mysqli_whartever($link, $functionContents);
***/
mysql_real_escape_string($size['mime']),
mysql_real_escape_string($imgData),
$size[3],
mysql_real_escape_string($_FILES['userfile']['name'])
);mysql_query($sql);您可以在以下网页中显示数据库中的图像：$link = mysql_connect("localhost", "username", "password");mysql_select_db("testblob");$sql = "SELECT image FROM testblob WHERE image_id=0";$result = mysql_query("$sql");header("Content-type: image/jpeg");echo mysql_result($result, 0);mysql_close($link);