JS 对数组的操作

Question

leta=[['1010','20','10'],['3010','40','20']]
letb=[
{
KUNN2:"0000000001",
PARVW_TEXT:"收款方",
VKORG:'3010',
VTWEG:'40',
VSBED:'20'
},
{
KUNN2:"0000000002",
PARVW_TEXT:"收款方",
VKORG:'1010',
VTWEG:'20',
VSBED:'10'
},
{
KUNN2:"0000000003",
PARVW_TEXT:"收款方",
VKORG:'4100',
VTWEG:'30',
VSBED:'10'
},
{
KUNN2:"0000000004",
PARVW_TEXT:"收款方",
VKORG:'3010',
VTWEG:'40',
VSBED:'20'
},
{
KUNN2:"0000000005",
PARVW_TEXT:"收款方",
VKORG:'1010',
VTWEG:'20',
VSBED:'10'
}
]
如上面2面2个数组，数组a是匹配项，随后我想要的结果是
letc=[[{KUNN2:"0000000002",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'},{KUNN2:"0000000005",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'}],[{KUNN2:"0000000001",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'},{KUNN2:"0000000004",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'}]]
希望各位大佬指教，不甚感激。###题目描述
题目来源及自己的思路
相关代码
//请把代码文本粘贴到下方（请勿用图片代替代码）
你期待的结果是什么？实际看到的错误信息又是什么？

Answer 1

应该是你想要的吧leta=[['1010','20','10'],['3010','40','20']]letb=[{KUNN2:"0000000001",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'},{KUNN2:"0000000002",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'},{KUNN2:"0000000003",PARVW_TEXT:"收款方",VKORG:'4100',VTWEG:'30',VSBED:'10'},{KUNN2:"0000000004",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'},{KUNN2:"0000000005",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'}]constresult=[];for(constaItemofa){constbFilter=b.filter(({VKORG,VTWEG,VSBED})=>VKORG===aItem[0]&&VTWEG===aItem[1]&&VSBED===aItem[2]);bFilter.length>0&&result.push(bFilter);}console.log(result);

Answer 2

1.你给的a数组，第一个值应该是1010对吧，2.a数组的值，我能过目测是分别与VKORG，VTWEG，VBED三个值相对应的，有没有不对应的需求，如果是对应的，哪就按下面代码来就可以leta=[['1010','20','10'],['3010','40','20']]letb=[{KUNN2:"0000000001",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'},{KUNN2:"0000000002",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'},{KUNN2:"0000000003",PARVW_TEXT:"收款方",VKORG:'4100',VTWEG:'30',VSBED:'10'},{KUNN2:"0000000004",PARVW_TEXT:"收款方",VKORG:'3010',VTWEG:'40',VSBED:'20'},{KUNN2:"0000000005",PARVW_TEXT:"收款方",VKORG:'1010',VTWEG:'20',VSBED:'10'}]letc=b.filter((item)=>{letindex=a.find((arr)=>{returnarr[0]===item.VKORG&&arr[1]===item.VTWEG&&arr[2]===item.VSBED})if(index){returnitem}})console.log(c)第二种方法，判断只要obj里的值含有数组里的值就返回，从你的回复里看到，a数组的子数组个数也不确定，但是问题如果存在以下数据，也会被返回{KUNN2:"0000000001",PARVW_TEXT:"收款方",VKORG:'10',VTWEG:'1010',VSBED:'20'}用下面的方法，这样的数据也是匹配的。letd=a.map((keys)=>{letres=b.filter((item)=>{letobjarr=Object.values(item)letoldlength=objarr.length//以下代码用于判断数组是否为另一个数组的子集，采用的方法是把两个数组合并，再去重后的数组长度等于原数组长度，则判定子集匹配。letnewarr=[...objarr,...keys]letnewlength=[...newSet(newarr)].lengthif(oldlength===newlength){returnitem}})returnres})