ES6 Generator的问题

Question

jsvarp=function*(){
yield"1";
console.log(2);
}
vart=p();
varvalue=t.next();
t.next();
console.log(value);
为什么这里yield只有一个却可以要调用两次next才能done呢？

Answer 1

试下这几段代码的运行结果，就是@Honwhy给的结论。1、javascript'usestrict';function*fibonacci(){console.log("hello");}letseq=fibonacci();2、javascript'usestrict';function*fibonacci(){console.log("hello");}letseq=fibonacci();seq.next();3、javascript'usestrict';function*fibonacci(){yield;console.log("hello");}letseq=fibonacci();seq.next();seq.next();