es6,从一个数组中删除另一个数组包含的内容

Question

我的代码有bug，然后查了下是把==写成了=

A [1,2,3,4,5,6,7]

B [2,3,4]

删除后

A [1,5,6,7]

    this.selectRightTableData.forEach(item => {

      this.rightTableData.splice(this.rightTableData.findIndex(v => v.id = item.id), 1)

    })

  

修复后，根据对象某个属性判断；是否相同

  

      

    this.selectRightTableData.forEach(item => {

      this.rightTableData.splice(this.rightTableData.findIndex(v => v.id == item.id), 1)

    })

  

根据内存地址判断

this.selectLeftTableData.forEach(item => {

      this.leftTableData.splice(this.leftTableData.indexOf(item), 1)

    })

Answer 1

感觉还没有new array ,然后 indexOf往新数组push方便    const a = [1,2,3,4,5], b = [1,2],c = [];    a.forEach( v => {      if(b.indexOf(v) === -1) c.push(v)    })

Answer 2

let A=[1,2,3,4,5,6,7];let B=[2,3,4];let newB=[];for(var i=0,lenA=A.length;i<lenA;i++){&nbsp; &nbsp; for(var b=0,lenB=B.length;b<lenB;b++){&nbsp; &nbsp; &nbsp; &nbsp; if(A[i]!=B[b]){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; newB.push(B[b])&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}这样也可以达到你想要的效果