猿问

PHP GuzzleHttp 无法获取到返回结果

$client = new GuzzleHttp\Client;
$response = $client->request('POST', 'http://www.jgggbbs.cn/member.php?mod=logging&action=login&loginsubmit=yes&handlekey=login&loginhash=LRTTI&inajax=1', array(
    'form_params' => array(
        'username'=>'test',
        'password'=>'fwefwegweg'
    ),
    'allow_redirects' => true,
    'headers' => [
        'User-Agent' => 'Mozilla/5.0 (Windows NT 10.0; …) Gecko/20100101 Firefox/61.0',
        'content-type' => 'application/x-www-form-urlencoded',
        'cache-control'      => 'no-cache'
    ]
));
print_r($response->getBody()); //这里输出为空,无法获取到返回结果

用PHP GuzzleHttp来登录某个论坛,这里先不管用户名和密码有没有错,也不管提交的参数有没有错,即使有错,网站也会返回出错的文字提示,但是现在我获取不到任何返回的文字,请问是怎么回事呢?

下面是改用php curl来发送这请求,这个能获取到返回结果(同样先不管是否登录成功,只要有返回结果就行):

$curl = curl_init();

curl_setopt_array($curl, array(
  CURLOPT_URL => "http://www.jgggbbs.cn/member.php?mod=logging&action=login&loginsubmit=yes&handlekey=login&loginhash=LRTTI&inajax=1",
  CURLOPT_RETURNTRANSFER => true,
  CURLOPT_ENCODING => "",
  CURLOPT_MAXREDIRS => 10,
  CURLOPT_TIMEOUT => 30,
  CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
  CURLOPT_CUSTOMREQUEST => "POST",
  CURLOPT_POSTFIELDS => "username=test&password=test",
  CURLOPT_HTTPHEADER => array(
    "cache-control: no-cache",
    "content-type: application/x-www-form-urlencoded"
  ),
));

$response = curl_exec($curl);
$err = curl_error($curl);

curl_close($curl);

if ($err) {
  echo "cURL Error #:" . $err;
} else {
  echo $response; //这里能获取反返回结果
}
温温酱
浏览 3840回答 2
2回答

九州编程

json_decode($response->getBody()->getContents(), true)

浮云间

先看看状态码吧 $response->getStatusCode(); 正常的 $response->getBody() 返回的 stream 对象
随时随地看视频慕课网APP
我要回答