请问下redux-saga如何回调处理自己的业务逻辑?

Question

如题，如何处理redux-saga的回调，调用自己的方法，比如，执行了saga后清除表单的输入，或者弹出成功信息框，或者跳转页面等等

import { call, put, takeLatest } from 'redux-saga/effects'import { fetch } from '@/util/request'import { message } from 'antd'import { push } from 'react-router-redux'import { CREATE_TASKGRAP, createTaskGrapSuccess, createTaskGrapFailed } from '../../actions/drawTaskGrapAction'const apifetch = (drawTaskGrap) => {    return fetch('drawTaskGrap', drawTaskGrap)
}export function* DrawTaskGrapData(actions){    try{        yield takeLatest(CREATE_TASKGRAP, DrawTaskGrapData);        const res = yield call(apifetch, actions.taskGrapObj);        console.log('draw task grap saga = ', res);        
        yield put(createTaskGrapSuccess(res.data))
    }catch(error){        yield put(createTaskGrapFailed(error.message))
    }
}

Answer 1

我自己写了个解决方法：this.props.dispatch(createTaskGrap({                     task:{                         activities: activities,                         remark: "",                         srcJson: modelTxt,                         templateName: "",                     },                    // 声明你的方法，方法体里面的逻辑自己实现就好                     testFn:()=>{                        //your do                     }             }))然后在saga里面执行：export function* DrawTaskGrapData(actions){    try{        yield takeLatest(CREATE_TASKGRAP, DrawTaskGrapData);        const res = yield call(apifetch, actions.taskGrapObj.task);        // 调用想要执行的方法         actions.taskGrapObj.testFn();        yield put(createTaskGrapSuccess(res.data))     }catch(error){        yield put(createTaskGrapFailed(error.message))     } }