typescript中引用better-scroll

Question

typescript中引用better-scroll,代码如下

import * as BScroll from 'better-scroll'

...

console.log(BScroll)

new BScroll('.wrapper')

...

控制台输出

{default: ƒ, __esModule: true}

> default:ƒ BScroll(el, options)

  __esModule:true

> __proto__:Object

> Uncaught TypeError: BScroll is not a constructor

...

检查作者package.json中types声明没问题

...

  "types": "./types/index.d.ts",

...

检查作者*.d.ts没问题

...

declare const BScroll: BScrollStatic;

declare module 'better-scroll' {

  export = BScroll;

}

...

求助，我这里是哪里错误了？

Answer 1

问题在于这句话 new BScroll('.wrapper'),错误很明显了，BScroll 不是一个构造器函数， 所以你不能使用new运算符。你应该可以直接这么用吧BScroll('.wrapper').

Answer 2

import * as BScroll from 'better-scroll'new BScroll.BScroll();import  BScroll from 'better-scroll'new BScroll();