跟当前时间比较，显示时间差距？

Question

如图：

将日期跟当前时间比较，并显示相差的时间如图展示，想封装一个方法，但是具体不知道该怎么弄好，求大神指点迷津。

自己在各路大神点思路下，自己给弄了一个，如下：

Answer 1

考虑下年、月、日、时、分的情况，主要是通过对比时间，分成六个级别【年、月、日、时、分、1分钟内】，哪个级别匹配到了就拿出结果即可：function diffTime(dataStr){&nbsp; &nbsp; var nowDate = new Date().getTime(),&nbsp; &nbsp; &nbsp; &nbsp; oldDate = new Date(dataStr).getTime(),&nbsp; &nbsp; &nbsp; &nbsp; diffTime = parseInt((nowDate - oldDate)/1000,10),&nbsp; &nbsp; &nbsp; &nbsp; oneMinute = 60,&nbsp; &nbsp; &nbsp; &nbsp; oneHour = 60 * oneMinute,&nbsp; &nbsp; &nbsp; &nbsp; oneDay = 24 * oneHour,&nbsp; &nbsp; &nbsp; &nbsp; oneMonth = 30 * oneDay,&nbsp; &nbsp; &nbsp; &nbsp; oneYear = 12 * oneMonth,&nbsp; &nbsp; &nbsp; &nbsp; compareArr = [oneYear,oneMonth,oneDay,oneHour,oneMinute],&nbsp; &nbsp; &nbsp; &nbsp; postfix = ['年前','个月前','天前','个小时前','分钟前','1分钟内'],&nbsp; &nbsp; &nbsp; &nbsp; diffYear,diffMonth,diffDay,diffHour,diffMinute,len=5;&nbsp; &nbsp; for(var i =0; i< len ;i++){&nbsp; &nbsp; &nbsp; &nbsp; var diff = Math.floor(diffTime/compareArr[i]);&nbsp; &nbsp; &nbsp; &nbsp; if(diff > 0){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; return diff + postfix[i];&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; else if(i === len -1 && diff === 0){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; return postfix[len];&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}