js 16进制编码字符串拼接不等于硬编码值

Question

var a = '\xe5\xbc\xdb\xe6\xca\xff\xec\xf9',

b='\\x'+['e5','bc','db','e6','ca','ff','ec','f9'].join('\\x')

// b eauqal a on literal, but b!=a

Answer 1

两者不相等的，\x 不能在运行时解析，当然如果用 eval 黑魔法的话var a = '\xe5\xbc\xdb\xe6\xca\xff\xec\xf9';eval(`var b = "\\x${['e5','bc','db','e6','ca','ff','ec','f9'].join('\\x')}"`)a === b // true正确的方式应该是用 String.fromCodePointString.fromCodePoint(...['e5','bc','db','e6','ca','ff','ec','f9'].map(el => parseInt(el, 16)))