猿问

C#中将double值变成二进制然后写入文件,Java中载入该文件读取此二进制double值时不正确

目前已定位到是因为C#中的byte范围是0到255,而java中byte值为-128到127导致的错误。

尝试过使用C#的sbyte来解决:

bw1 = new BinaryWriter(new FileStream("C:\\Users\\DELL\\Desktop\\SpatialIndex\\ctest1.bin", FileMode.Create));
 bw2 = new BinaryWriter(new FileStream("C:\\Users\\DELL\\Desktop\\SpatialIndex\\ctest2.bin", FileMode.Create));      

        
  byte[] bits=BitConverter.GetBytes(501751.060001268);//测试数据
                sbyte[] bitsb = new sbyte[8];
                for (int i = 0; i < bits.Length; i++)
                {
                    byte abyte = bits[i];
                    if (abyte > 127)
                    {
                        bitsb[i] = (sbyte)(abyte - 256);
                    }
                    else
                    {
                        bitsb[i] = (sbyte)abyte;
                    }
                    bw1.Write(bitsb[i]);
                    bw2.Write(bits[i]);
                } 

 

但是写入后对比,两个文件中的内容还是一样,并没有生成为java二进制格式。

 

不知道有哪位高人也遇到并解决过类似问题。           

慕码人2483693
浏览 524回答 2
2回答

慕工程0101907

public static sbyte[] ToJavaBytes(byte[] bytes) { int len = bytes.Length; sbyte[] sbs = new sbyte[len]; for (int i = 0; i < len; i++) { var b = bytes[i]; if (b > 127) { sbs[len - 1 - i] = (sbyte)(b - 256); } else { sbs[len - 1 - i] = (sbyte)b; } } return sbs; }  
随时随地看视频慕课网APP

相关分类

Java
我要回答