一道小数学题，用for循环怎么实现？

Question

题目：计算从1开始的连续n个自然数之和，当其和值刚好超过100时结束，求n

代码：

var sum = 0;
var n = 0;
while(sum <= 100){  
  n++;    
  sum +=n;
}
console.log(sum);
console.log(n);

问题：这道题用for循环怎么实现呢？

Answer 1

function a(count){&nbsp; &nbsp; var sum =0;&nbsp; &nbsp; for(var i=1;i<count;i++){&nbsp; &nbsp; &nbsp; &nbsp; if(sum >count){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; console.log(i-1);&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; sum +=i;&nbsp; &nbsp; }}a(100);//求累加值刚好超过100，参数传100，求累加值刚好超过1000，参数传1000，

Answer 2

var sum = 0;&nbsp; &nbsp; for(var i = 0;i<=i;i++){&nbsp; &nbsp; &nbsp; &nbsp; if(sum >= 100){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break;&nbsp; &nbsp; &nbsp; &nbsp; }else{&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; sum += i;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; console.log('i =' +(i-1)); &nbsp;//i = 14&nbsp; &nbsp; console.log('sum = '+sum); //sum = 105