怎么让if(newPage ! = "")不报错

我这需要newPage不等于空,要怎么改啊,大神们

Uncaught SyntaxError: Unexpected token !报这个错误

window.onload = initForm;

window.onunload = function(){};

function initForm(){

document.getElementById("newLocation").selectedIndex = 0;

document.getElementById("newLocation").onchange = jumppage;

}

function jumppage(){

var newLoc = document.getElementById("newLocation");

var newPage = newLoc.option[newLoc.selectedIndex].value;

if(newPage ! = ''){

window.location = newPage;

}

Yeah___

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3回答

慕运维7130634

<!DOCTYPE html><html> <head> <meta charset="UTF-8"> <title></title> </head> <body> <script> var newPage; if(newPage!=""){ alert(1)//不报错 } </script> </body></html>

慕运维7130634

你叫我怎么帮你？

慕运维7130634

上代码

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