C语言编程

Answer 1

看你这个我测着头看得好累int main(){    double i;    int bon,bon1,bon2,bon4,bon6,bon10;    printf("请输入利润i:")；    scanf("%d",&i);    bon1=100000*0.1;    bon2=bon1+100000*0.075;    bon4=bon2+200000*0.05;    bon6=bon4+200000*0.03;    bon10=bon6+400000*0.015;if(i<=100000){bon=i*0.1;}else if(i<=200000){bon=bon1+(i-100000)*0.075;}else if(i<=400000){bon=bon2+(i-200000)*0.05;}else if(i<=600000){bon=bon4+(i-400000)*0.03;}else if(i<=1000000){bon=bon6+(i-600000)*0.01;}else{bon=bon10+(i-1000000)*0.01;}printf("提成为:bon=%f",bon);}