这句JS能写的更简单吗？

Question

options.async=options.async.toLowerCase()=='false'?false:true;

在phpstorm有个报错

        'options.async.toLowerCase()=='false'?false:true' can be simplified to    'options.async.toLowerCase()!='false'' 更少...    (Ctrl+F1)

This inspection reports any instances of JavaScript conditional      expressions of the form condition?true:false      or condition?false:true.      These expressions may be safely simplified to condition      or !condition , respectively. 

所以随便问

Answer 1

能，options.async=options.async.toLowerCase()=='false'?false:true;你这句的意思就是，当值等于false时，返回false，那么好了，当值不等于false时返回true，那么可以优化成：options.async=options.async.toLowerCase()!='false';