猿问

ssm框架做登录测试时,如何把url栏中的.action伪装变成.html?用urlrewrite这个东东。


--urlrewrite.xml
<?xml version="1.0" encoding="utf-8"?>    
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"    "http://tuckey.org/res/dtds/urlrewrite2.6.dtd" >

<urlrewrite>
	<rule>
		<from>/index.html</from>
		<to type="forward">/index.jsp</to>
	</rule>
	<rule>
		<from>/([a-zA-Z0-9_\u4e00-\u9fa5]+).html</from>
		<to type="forward">/ssmTest/$1.action</to>
	</rule>
</urlrewrite>
--web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:spring*.xml</param-value>
  </context-param>
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>
  <filter>
    <filter-name>struts2</filter-name>
    <filter-class>org.apache.struts2.dispatcher.filter.StrutsPrepareAndExecuteFilter</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>struts2</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>
    <dispatcher>FORWARD</dispatcher>
  </filter-mapping>
  
  <filter>  
    <filter-name>UrlRewriteFilter</filter-name>  
    <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>  
</filter>  
<filter-mapping>  
    <filter-name>UrlRewriteFilter</filter-name>  
    <url-pattern>/*</url-pattern>  
</filter-mapping> 
<welcome-file-list>
	<welcome-file>index.jsp</welcome-file>
	<welcome-file>*.html</welcome-file>
</welcome-file-list>
</web-app>
--struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
	"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
	"http://struts.apache.org/dtds/struts-2.3.dtd">

<struts>

	<constant name="struts.enable.DynamicMethodInvocation" value="false" />
	<constant name="struts.devMode" value="true" />

	<!-- 把struts的action对象交给spring容器管理 -->
	<constant name="struts.objectFactory " value="spring" />

	<package name="default" namespace="/" extends="struts-default">
		
		<action name="*_*" class="{1}Action" method="{2}">
			<result name="loginsuccess">page/success.jsp</result>
			<result name="loginfail" type="redirect">index.jsp</result>
		</action>
	</package>
	
</struts>

问题来了:::

把localhost:8080/ssmTest/user_login.action登录跳转时变成localhost:8080/ssmTest/user_login.html

Bobzhangxiaotao
浏览 5866回答 1
1回答

yemaa

在web.xml配置<filter-mapping>  <filter-name>struts2</filter-name>  <url-pattern>*.html</url-pattern> </filter-mapping>
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