问答详情
源自:4-1 对象继承-PHP面向对象编程

为什么我name输不出来,求指教,跪谢

<?php
date_default_timezone_get('PRC');
/**
* Created by PhpStorm.
* User: Administrator
* Date: 2015/8/16
* Time: 15:55
*/
class Human{
   public $name;
   public $height;
   public $weight;

   public function ect($food){
      echo $this->name."'s eating".$food;
   }
}
class NbaPlayer extends Human{
   public $team="bull";
   public $playerNumber="23";

   function __construct($name,$height,$weight,$team,$playerNumber){
       echo "构造函数调用成功";
   }
}
$jordan=new NbaPlayer("jordan","198cm","98kg","bull","23");
echo $jordan->name."\n";
$jordan->ect("Apple");

提问者:程序怨 2015-08-18 17:22

个回答

  • 关于淡淡的淡淡的
    2015-08-18 23:48:32
    已采纳

    因为你的构造函数什么都没做,只是输出了"构造函数调用成功" ,你只是定义了 name 属性,你在构造函数中加上一句  

    $this->name = $name;