个回答

• jason300614

  2014-11-25 16:39:39

  $filename = '/data/webroot/usercode/resource/test.txt';
  //编写代码读取$filename的文件内容
  $str = 'this is a test file.';
  $contents = file_put_contents($filename,$str);
  $newStr = file_get_contents($filename);
  echo $newStr;

  1