源自：4-6 Python之break跳出循环
有大神帮下吗？
提问者：officalwithhighran
2021-10-21 21:07
个回答
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- 慕粉2244596634
- 2021-10-21 21:46:51
num = 0 sum = 0 while True: if num > 1000: break if num % 2 == 0: sum = sum + num num = num + 1 print(sum)
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- 慕粉2244596634
- 2021-10-21 21:43:16
num = 1 sum = 0 while True: if num > 100: break sum = sum + num num = num + 1 print(sum)