int x = ( m * 8 / ( n + 2 ) ) % m ;

源自：3-8 Java中运算符的优先级

int x = ( m * 8 / ( n + 2 ) ) % m ;

int x = ( m * 8 % ( n + 2 ) )

m=5

n=7

x=4

这样才正确吧

提问者：慕盖茨3434532 2021-08-14 17:47

个回答

慕瓜8049783

2021-08-15 10:04:22

(n+2)优先运算，n+2=9;
m*8/9=4.4444444....
4%5=4,所以最后应该是4

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