#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
/*
* 请使用switch语句，if...else语句完成本题
* 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
int sum;
if(year/4==0)
{
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
}
}
else
{
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=60;break;
case 4:sum=91;break;
case 5:sum=121;break;
case 6:sum=153;break;
case 7:sum=182;break;
case 8:sum=213;break;
case 9:sum=244;break;
case 10:sum=274;break;
case 11:sum=305;break;
case 12:sum=335;break;
}
}
sum+=day;
printf("%d年%d月%d日是该年的第%d天"，year，month，day,sum);
return 0;
}
#include <stdio.h>int main() { int year = 2008; int month = 8; int day = 8; int x, sum; switch (month) { case 1: sum = 0; break; case 2: sum = 31; break; case 3: sum = 60; break; case 4: sum = 91; break; case 5: sum = 121; break; case 6: sum = 152; break; case 7: sum = 182; break; case 8: sum = 213; break; case 9: sum = 244; break; case 10: sum = 274; break; case 11: sum = 305; break; case 12: sum = 335; break; default: printf("一年只有12个月哟！！！"); break; } sum = sum + day; if ((year % 4 == 0 && year % 100 != 0 ) || year % 400 == 0) { x = 1;//该年为闰年，则定义为1，否则为0。 } else { x = 0; } if (x = 0 && month > 2) sum++; printf("%d年%d月%d日是该年的第%d天。", year, month, day, sum); return 0;}printf("%d年%d月%d日是该年的第%d天"，year，month，day,sum);
前三个逗号是中文的
好像是你的逗号没用英文状态
你的最后一句输出的逗号要用英文状态下输入。