#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int sum =0,flag=0;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
switch(month)
{
case 1:
sum=0;
case 2:
sum=31;
break;
case 3:
sum=59;
break;
case 4:
sum=90;
break;
case 5:
sum=120;
break;
case 6:
sum=151;
break;
case 7:
sum=181;
break;
case 8:
sum=212;
break;
case 9:
sum=243;
break;
case 10:
sum=273;
break;
case 11:
sum=304;
break;
case 12:
sum=334;
break;
default:
printf("一年只有12个月");
break;
}
sum=sum+day;
if(year%400==0||(year%4==0&&year%100!=0))
flag=1;
else
flag=0;
if(flag==1&&month>2)
sum++;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
return 0;
}
case 1:
sum=0;后面少了个break吗?