#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
int sum,n;
switch(month)
{
case 1: sum=0;break;
case 2: sum=31;break;
case 3: sum=31+28;break;
case 4: sum=31+28+31;break;
case 5: sum=31+28+31+30;break;
case 6: sum=31+28+31+30+31;break;
case 7: sum=31+28+31+30+31+30;break;
case 8: sum=31+28+31+30+31+30+31;break;
case 9: sum=31+28+31+30+31+30+31+30;break;
case 10: sum=31+28+31+30+31+30+31+30+31;break;
case 11: sum=31+28+31+30+31+30+31+30+31+30;break;
case 12: sum=31+28+31+30+31+30+31+30+31+30+31;break;
default:printf("一年中只有十二个月哦");break;
}
sum=sum+day;
if(year%4==0&&year%100!=0)
n=1;
else
n=0;
if(n==1&&month>2)
sum++;
printf("%d年%d月%d日是该年的第%d天",year,month,day,sum);
return 0;
}
return 0;
}
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int sum=0;
int m;
for(m=1;m<month;m++)
{
switch(m)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
sum+=31;break;
case 2:
if((year%4==0&&year%100!=0)||year%400==0)
sum+=29;
else
sum+=28;
break;
case 4: case 6: case 9: case 11:
sum+=30;
break;
}
}
sum+=day;
printf("这是第%d天",sum);
return 0;
}
兄弟你最后多了一个 return 0; 你把后面那几行去掉就行了