源自：4-3 指示器动画实现2
字体颜色变不了
切换字体颜色的代码
private int evaluate(float progress, int startValue, int endValue) {
int startA = (startValue >> 24) & 0xff;
int startR = (startValue >> 16) & 0xff;
int startG = (startValue >> 8) & 0xff;
int startB = startValue & 0xff;
int endA = (endValue >> 24) & 0xff;
int endR = (endValue >> 16) & 0xff;
int endG = (endValue >> 8) & 0xff;
int endB = endValue & 0xff;
return (int)((startA + (int) progress * (endA - startA))) << 24 |
(int)((startR + (int) progress * (endR - startR))) << 16 |
(int)((startG + (int) progress * (endG - startG))) << 8 |
(int) ((startB + (int) progress * (endB - startB)));
}
if (positionOffset > 0) {
TabView left = mTabs.get(position);
TabView right = mTabs.get(position + 1);
left.setProgress((1 - positionOffset));
right.setProgress(positionOffset);
}
提问者：慕移动9209807
2019-04-23 09:09
个回答
-
- 慕虎6181031
- 2019-11-12 16:18:29
private int evaluate(float fraction, int startValue, int endValue) { int startInt = (Integer) startValue; float startA = ((startInt >> 24) & 0xff) / 255.0f; float startR = ((startInt >> 16) & 0xff) / 255.0f; float startG = ((startInt >> 8) & 0xff) / 255.0f; float startB = ( startInt & 0xff) / 255.0f; int endInt = (Integer) endValue; float endA = ((endInt >> 24) & 0xff) / 255.0f; float endR = ((endInt >> 16) & 0xff) / 255.0f; float endG = ((endInt >> 8) & 0xff) / 255.0f; float endB = ( endInt & 0xff) / 255.0f; // convert from sRGB to linear startR = (float) Math.pow(startR, 2.2); startG = (float) Math.pow(startG, 2.2); startB = (float) Math.pow(startB, 2.2); endR = (float) Math.pow(endR, 2.2); endG = (float) Math.pow(endG, 2.2); endB = (float) Math.pow(endB, 2.2); // compute the interpolated color in linear space float a = startA + fraction * (endA - startA); float r = startR + fraction * (endR - startR); float g = startG + fraction * (endG - startG); float b = startB + fraction * (endB - startB); // convert back to sRGB in the [0..255] range a = a * 255.0f; r = (float) Math.pow(r, 1.0 / 2.2) * 255.0f; g = (float) Math.pow(g, 1.0 / 2.2) * 255.0f; b = (float) Math.pow(b, 1.0 / 2.2) * 255.0f; return Math.round(a) << 24 | Math.round(r) << 16 | Math.round(g) << 8 | Math.round(b); } -
- 坚持2016
- 2019-04-30 20:27:37
没有看出来哪里有问题