问答详情
源自:9-14 删除节点removeChild()

这个应该没有问题吧


<!DOCTYPE HTML>

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8">

<title>无标题文档</title>

</head>


<body>

<div id="content">

  <h1>html</h1>

  <h1>php</h1>

  <h1>javascript</h1>

  <h1>jquery</h1>

  <h1>java</h1>

</div>


<script type="text/javascript">

function clearText() {

  var content=document.getElementById("content");

  // 在此完成该函数

  var son = content.childNodes;

  for(i=1;i<son.length;i++){

      var x = content.removeChild(son[i]);

    

  

  }

  

}

</script>


<button onclick="clearText()">清除节点内容</button>




</body>

</html>


提问者:慕婉清7358510 2018-11-20 13:57

个回答

  • 慕慕0508951
    2018-11-27 17:59:55

    <!DOCTYPE HTML>

    <html>

    <head>

    <meta http-equiv="Content-Type" content="text/html; charset=utf-8">

    <title>无标题文档</title>

    </head>


    <body>

    <div id="content">

      <h1>html</h1>

      <h1>php</h1>

      <h1>javascript</h1>

      <h1>jquery</h1>

      <h1>java</h1>

    </div>


    <script type="text/javascript">

    function clearText() {

      var content=document.getElementById("content");

      // 在此完成该函数

      var con = content.childNodes;

      for(var i=0;i<con.length;i++){

          content.removeChild(con[i]);

      }

      clearText();

      

    }

    </script>


    <button onclick="clearText()">清除节点内容</button>




    </body>

    </html>