public class EmployeeDaoImpl extends HibernateDaoSupport implements EmployeeDao{
//DAO中根据用户名和密码查询用户的方法(HQL查询)
@Override
public Employee findByUsernameAndPassword(Employee employee) {
String hql="from Employee where username = :username and password = :password";
List<?> list=this.getHibernateTemplate().find(hql, employee.getUsername(),employee.getPassword());
if (list.size()>0) {
return (Employee) list.get(0);
}else {
return null;
}
}
}代码如上，报500错误……实在解决不来，求各位帮帮忙
使用的hibernate版本是5.3.2
getHibernateTemplate().findByNamedParam(hql,{"username","password"},{第一个值，第二个值})
顺便提一句更新后的?变为?1 风格变了需要在后边加上序号
String hql="from Employee where username = :username and password = :password";改
String hql="from Employee where username = ?0 and password = ?1;
"from Employee where username = ? and password = ?" 这样写试试？