个回答

• MartinKay

  2018-09-06 19:52:36

  

  请常考这个！

  0

• 慕UI3564028

  2018-09-05 17:03:36

  判断是不是闰年就行啦

  #include <stdio.h>
  int main()
  {
      /* 定义需要计算的日期 */
      int year = 2008;
      int month = 8;
      int day = 8;
      int i,num;//i用来表示2月的28天是否该加一,num表示和
      if((year%400==0&&year%100==0)||year%4==0)//判定是否是闰年
          i=1;
      else
          i=0;
      switch(month)
         {
          case 1:num=i+day;break;
          case 2:num=i+day+31;break;
          case 3:num=i+day+31+28;break;
          case 4:num=i+day+31+28+31;break;
          case 5:num=i+day+31+28+31+30;break;
          case 6:num=i+day+31+28+31+30+31;break;
          case 7:num=i+day+31+28+31+30+31+30;break;
          case 8:num=i+day+31+28+31+30+31+30+31;break;
          case 9:num=i+day+31+28+31+30+31+30+31+31;break;
          case 10:num=i+day+31+28+31+30+31+30+31+31+30;break;
          case 11:num=i+day+31+28+31+30+31+30+31+31+30+31;break;
          case 12:num=i+day+31+28+31+30+31+30+31+31+30+31+30;break;
         }
      printf("%d年%d月%d日是该年的第%d天",year,month,day,num);
   return 0;
  }

  0