#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int i,j;
if((year%100 != 0 && year%4 == 0)||year%400 == 0)
{
i = 28;
}
else
{
i = 27;
}
switch(month)
{
case 1:j = day; break;
case 2:j = 31 + day; break;
case 3:j = 31 + i + day; break;
case 4:j = 31 + i + 31 + day; break;
case 5:j = 31 + i + 31 + 30 + day; break;
case 6:j = 31 + i + 31 + 30 + 31 + day; break;
case 7:j = 31 + i + 31 + 30 + 31 + 30 + day; break;
case 8:j = 31 + i + 31 + 30 + 31 + 30 + 31 + day; break;
case 9:j = 31 + i + 31 + 30 + 31 + 30 + 31 + 31 + day; break;
case 10:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + day; break;
case 11:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + day; break;
case 12:j =31 + i + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + day; break;
}
printf("%d年%d月%d日是该年中的第%d天"), year, month, day, j);
/*
* 请使用switch语句，if...else语句完成本题
* 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
return 0;
}
#include <stdio.h>
int main()
{
int year = 2008;
int month = 8;
int day = 8;
int Day,i;
if(year%400==0||(year%4==0&&year%100!=0))
{
i=29;
}
else
{
i=28;
}
switch(month)
{
case 1: Day=day;break;
case 2: Day=i+day;break;
case 3: Day=i+31+day;break;
case 4: Day=i+31+30+day;break;
case 5: Day=i+31+30+31+day;break;
case 6: Day=i+31+30+31+30+day;break;
case 7: Day=i+31+30+31+30+31+day;break;
case 8: Day=i+31+30+31+30+31+31+day;break;
case 9: Day=i+31+30+31+30+31+31+30+day;break;
case 10: Day=i+31+30+31+30+31+31+30+31+day;break;
case 11: Day=i+31+30+31+30+31+31+30+31+30+day;break;
case 12: Day=i+31+30+31+30+31+31+30+31+30+31+day;break;
}
printf("%d年%d月%d日是该年的第%d天\n",year,month,day,Day);
return 0；
}
我的这个过程跟你基本上一样，运行成功了。
兄弟，闰年2月是29天不是28天。。。。。。