#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int days;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
switch(month)
{
case 1:days=day;break;
case 2:days=31+day;break;
case 3:days=31+28+day;break;
case 4:days=31+28+31+day;break;
case 5:days=31+28+31+30+day;break;
case 6:days=31+28+31+30+31+day;break;
case 7:days=31+28+31+30+31+30+day;break;
case 8:days=31+28+31+30+31+30+31+day;break;
case 9:days=31+28+31+30+31+30+31+30+day;break;
case 10:days=31+28+31+30+31+30+31+30+31+day;break;
case 11:days=31+28+31+30+31+30+31+30+31+30+day;break;
default 12:days=31+28+31+30+31+30+31+30+31+30+31+day;break;
}
if(year%100==0&&year%400==0||year%4==0&&year%100!=0)
{
days=days+1;
}
printf(%d年%d月%d日是该年的第%d天,year);
else
printf(%d年%d月%d日是该年的第%d天,year,month,day,days);
return 0;
}
#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
int days,days1;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
switch(month)
{
case 1:
days=day;
break;
case 2:
days=31+day;
break;
case 3:
days=31+28+day;
break;
case 4:
days=31+28+31+day;
break;
case 5:
days=31+28+31+30+day;
break;
case 6:
days=31+28+31+30+31+day;
break;
case 7:
days=31+28+31+30+31+30+day;
break;
case 8:
days=31+28+31+30+31+30+31+day;
break;
case 9:
days=31+28+31+30+31+30+31+30+day;
break;
case 10:
days=31+28+31+30+31+30+31+30+31+day;
break;
case 11:
days=31+28+31+30+31+30+31+30+31+30+day;
break;
default :
days=31+28+31+30+31+30+31+30+31+30+31+day;
break;
}
if((year%4==0||year%400==0)&&year%100!=0)
{
days1=days+1;
printf("%d年%d月%d日是该年的第%d天",year,month,day,days1);
}
else
{
printf("%d年%d月%d日是该年的第%d天",year,month,day,days);
}
return 0;
}
printf输出语句括号内的引号没写
闰年时如果在一月或二月就不用加1;在判断闰年时前后两个并列条件要用括号;printf(%d年%d月%d日是该年的第%d天,year);没写完;你改改再试试,参考一下答案