为什么他提示检查输出是否包含：x%y=1

源自：3-2 算术运算符

#include <stdio.h>

int main()

{

int x,y;

x = 10;

y = -3;

int a1,a2,a3,a4,a5;

a1=x+y;

a2=x-y;

a3=x*y;

a4=x/y;

a5=x%y;

printf("x+y=%d\n",a1);

printf("x-y=%d\n",a2);

printf("x*y=%d\n",a3);

printf("x/y=%d\n",a4);

printf("x%y=%d\n",a5);

return 0;

}

提问者：qq_南风知我譩丷_0 2017-10-01 21:14