#include <stdio.h> int main() { /* 定义需要计算的日期 */ int year = 2008; int month = 8; int day = 8; /* * 请使用switch语句，if...else语句完成本题 * 如有想看小编思路的，可以点击左侧任务中的“不会了怎么办” * 小编还是希望大家独立完成哦~ */ int sum,m; switch(month) { case 1:sum=day;break; case 2:sum=31+day;break; case 3:sum=31+28+day;break; case 4:sum=31+28+31+day;break; case 5:sum=31+28+31+30+day;break; case 6:sum=31+28+31+30+31+day;break; case 7:sum=31+28+31+30+31+30+day;break; case 8:sum=31+28+31+30+31+30+31+day;break; case 9:sum=31+28+31+30+31+30+31+31+day;break; case 10:sum=31+28+31+30+31+30+31+31+30+day;break; case 11:sum=31+28+31+30+31+30+31+31+30+31+day;break; case 12:sum=31+28+31+30+31+30+31+31+30+31+30+day;break; } if(year%400==0||(year%4==0&&year%100==0)) m=1; else m=0; if(m==1&&month>2) sum++; printf("%d年%d月%d日是该年的第%d天"，year,month,day,sum); return 0; }