问答详情
源自:9-11 访问兄弟节点

用按钮实现访问兄弟节点?怎样点了按钮不消失?

  function next(){

      y=get_nextSibling(y);

     if(y!=null){

        document.write("<br />nextsibling: ");

        document.write(y.nodeName);

        document.write(" = ");

        document.write(y.innerHTML);

    }else{

      document.write("<br>已经是最后一个节点");      

    }

  

 

<input type="button" value="next" onclick="next()"/>

提问者:文刀笑 2017-08-01 12:07

个回答

  • 学习js
    2017-08-03 10:28:34
    已采纳

    http://img.mukewang.com/5982881e0001572002080207.jpg

    <!DOCTYPE HTML>

    <html>


    <head>

    <meta http-equiv="Content-Type" content="text/html; charset=utf-8">

    <title>nextSibling</title>

    </head>


    <body>

    <ul id="u1">

    <li id="a">javascript</li>

    <li id="b">jquery</li>

    <li id="c">html</li>

    </ul>

    <ul id="u2">

    <li id="d">css3</li>

    <li id="e">php</li>

    <li id="f">java</li>

    </ul>

    <div id="u3"></div>

    <input type="button" value="next" onclick="next()" />

    <script type="text/javascript">

    function get_nextSibling(n) {

    var x = n.nextSibling;

    while(x && x.nodeType != 1) {

    x = x.nextSibling;

    }

    return x;

    }

    function get_previousSibling(n) {

    var x = n.previousSibling;

    while(x && x.nodeType != 1) {

    x = x.previousSibling;

    }

    return x;

    }

    var x = document.getElementsByTagName("li")[0];

    document.write(x.nodeName);

    document.write(" = ");

    document.write(x.innerHTML);

    var y = get_nextSibling(x);

    function next() {

    y = get_nextSibling(y);

    if(y != null) {

    document.getElementById("u3").innerHTML="<br />next sibling: "+y.nodeName+"="+y.innerHTML

    } else {

    document.getElementById("u3").innerHTML="<br>已经是最后一个节点"

    }


    }

    </script> 

    </body>

    </html>

  • 学习js
    2017-08-01 16:43:17

    写个div,把你要输出的内容放到新的div里面