x=2,y=3,z=4,
((x+y)>z)&&(y==z)&&x||y+z&&y+z
#include <stdio.h>
int main() {
int x = 2,y = 3,z = 4;
printf("%c\n",((x+y)>z)&&(y==z)&&x||y+z&&y+z?'y':'n');
return 0;
}
#include <stdio.h> int main() { int x = 2,y = 3,z = 4; if(((x+y)>z)&&(y==z)&&x||y+z&&y+z) printf("true"); eles printf("false") return 0; }