个回答

• qq_大雄_11

  2017-03-03 23:47:39

  已采纳

   var infos=[["小A","女",21,"大一"],["小B","男",23,"大三"],["小C","男",24,"大四"],["小D","女",21,"大一"],["小E","女",22,"大四"],["小F","男",21,"大一"],["小G","女",22,"大二"],["小H","女",20,"大三"],["小I","女",20,"大一"],["小J","男",20,"大三"]];

   

   //第一次筛选，找出都是大一的信息

   for (var i =0;i<infos.length;i++){

       if(infos[i][3] == "大一" && infos[i][1] == "女"){

           document.write(infos[i][0]+"<br/>");

       }

   }

    

  
  

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• qq_大雄_11

  2017-03-07 14:52:43

  for (var i =0;i<infos.length;i++),var i = 0,这个循环的开始值为0，对应的就是这个infos二维数组中第一维数组的下标（key），也就是infos[i],infos.length是infos二维数组中第一维的个数，之后就是循环遍历每一个infos的以为数组！

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