问答详情
源自：3-3 Java中的赋值运算符

请教一下我这个编法的问题所在

我是这样写的

int one = 10 ;

        int two = 20 ;

        int three = 0 ;

         three=one+two;

         three+=one;

         three-=one;

         three*=one;

         three/=one;

        three%=one;

         System.out.println("three%=one==>"+three);

         System.out.println("three/=one==>"+three);

         System.out.println("three*=one==>"+three);

        System.out.println("three-=one==>"+three);

         System.out.println("three+=one==>"+three);

        System.out.println("three=one+two==>"+three);

我这样写的话里面的three就恒是0 是不是一定要按照给的答案那样编写three才不会一直为0啊

恳请解答一下！

提问者：慕函数9227957 2017-02-08 14:26

个回答

  • 慕粉1904487852
    2017-02-08 14:38:27
    已采纳

    程序执行时从上到下的，假如你执行一句，就输出结果，那么就对了，因为变量的值时变的，要及时输出

    比如：

            int one = 10 ;

            int two = 20 ;

            int three = 0 ;

            three=one+two;

            System.out.println("three%=one==>"+three);

            three+=one;

            System.out.println("three/=one==>"+three);

            three-=one;

            System.out.println("three*=one==>"+three);

            three*=one;

            System.out.println("three-=one==>"+three);

            three/=one;

            System.out.println("three+=one==>"+three);

            three%=one;

            System.out.println("three=one+two==>"+three);

             这样就对了，

    这个是我写的（参考）：

             System.out.println("three = one + two ==> "+(three = one + two));

            System.out.println("three += one ==> "+(three += one));

            System.out.println("three -= one ==> "+(three -= one));

            System.out.println("three *= one ==> "+(three *= one));

            System.out.println("three /= one ==> "+(three /= one));

            System.out.println("three %= one ==> "+(three %= one));

            


    0