#include <stdio.h>
double c;
double cost(int t ,double d)
{
double p;
if(23<=t<=24||0<=t<5)
{
p=2.3*1.2;
}
else
{
p=2.3;
}
if(d<=3)
{
c=13;
return c+1;
}
else
{
c=13+(d-3)*p;
return c+1;
}
}
int main()
{
double c=cost(9,12)+cost(18,12);
printf("小明每天打车的总费用为%f元",c);
return 0;
}
69.4
将 if(23<=t<=24||0<=t<5)改成t>=23&&t<=24||t>=0&&t<5结果就正确啦，&&的优先级比||高，所以不用担心，会先运算完与再运算或的。
#include<stdio.h>
float Pay(int time,int dis)
{
float pay;
if(time>=23||time<5)
{
pay=14+(dis-3)*2.3*1.2;
}
else
{
pay=14+(dis-3)*2.3;
}
return pay;
}
int main()
{
printf("小明打车的总费用是%f元\n",Pay(9,12)+Pay(18,12));
return 0;
}