个回答

• ZERO_C

  2016-10-26 09:32:07

  已采纳

  #include<stdio.h>

  int main()

  {

      int i=1,n=0,a,b,c;
  

      for(i=1;i<600;i++)

      {

          a=i/100;
  

          b=(i%100)/100;
  

          c=(i%100)%10;
  

          if(i%3==0&&(a==5||b==5||c==5))
  

          {

              printf("%4d",i);
  

              n++;
  

              if(n%6==0)
  

              printf("\n");
  

          }
  

      }
  

  printf("\n%d",n);

  return 0;

  }

  1