问答详情
源自:9-11 访问兄弟节点

大神们帮忙看下哪里有问题啊

<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>nextSibling</title>
</head>
<body>
<ul id="u1">   
            <li id="a">javascript</li>   
            <li id="b">jquery</li>   
            <li id="c">html</li>   
        </ul>   
        <ul id="u2">   
            <li id="d">css3</li>   
            <li id="e">php</li>   
            <li id="f">java</li>   
        </ul>   
<script type="text/javascript">
    function get_nextSibling(n){
        var x=n.nextSibling;
        while (x && x.nodeType!=1){
            x=x.nextSibling;
        }
        return x;
    }

    var x=document.getElementsByTagName("li")[0];
    document.write(x.nodeName);
    document.write(" = ");
    document.write(x.innerHTML);
    
    var y=get_nextSibling(x);
    
    if(y!=null){
        document.write("<br />nextsibling: ");
        document.write(y.nodeName);
        document.write(" = ");
        document.write(y.innerHTML+"</br>");
    }else{
      document.write("<br>已经是最后一个节点");      
    }
    
    function get_previousSibling(n)
    {
        var i=n.previousSibling;
        while(i&i.nodeType!=1)
        {
            i=i.previousSibling;
        }
        return i;
    }
    var i=document.getElementsByTagName("li")[5];
    document.write(i.nodeName);
    document.write("=");
    document.write(i.innerHTML);
    
    var g=get_previousSibling(i);
    if(g!=null)
    {
        document.write("</br>previousSibling:"+g.nodeName+"="+g.innerHTML);
       
    }
    else
    {
        document.write("</br>已经是第一个节点");
        }
    

</script>
</body>
</html>


提问者:qq_给自己一个微笑_0 2016-10-04 10:08

个回答

  • 地球一书生
    2016-10-04 22:58:55
    已采纳

    function get_previousSibling(n)

        {

            var i=n.previousSibling;

            while(i&i.nodeType!=1)

            {

                i=i.previousSibling;

            }

            return i;

        }

    这段代码第四行while()里面应为&&