为什么照着打却提示这种错误？

源自：3-4 BeautifulSoup使用

为什么照着打却提示这种错误？

D:\Python\Python35-32\python.exe D:/111/Pytest/bstest.py

Traceback (most recent call last):

File "D:/111/Pytest/bstest.py", line 17, in <module>

soup = bs(html_doc,"html.parser")

File "D:\Python\Python35-32\lib\site-packages\bs4\__init__.py", line 196, in __init__

self._feed()

File "D:\Python\Python35-32\lib\site-packages\bs4\__init__.py", line 210, in _feed

self.builder.feed(self.markup)

File "D:\Python\Python35-32\lib\site-packages\bs4\builder\_htmlparser.py", line 156, in feed

parser = BeautifulSoupHTMLParser(*args, **kwargs)

TypeError: __init__() got an unexpected keyword argument 'strict'

Process finished with exit code 1

===========================================

我照着老师那样打出现了这种错误提示，是哪里出了问题呢？下面是代码：

from bs4 import  BeautifulSoup as bs

html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title"><b>The Dormouse's story</b></p>

<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>

<p class="story">...</p>
"""

soup = bs(html_doc,"html.parser")

print(soup.prettify())

提问者：weibo_一万群什麼_0 2016-09-04 10:35

为什么照着打却提示这种错误？

个回答