#include <stdio.h>
int main()
{
/* 定义需要计算的日期 */
int year = 2008;
int month = 8;
int day = 8;
/*
* 请使用switch语句,if...else语句完成本题
* 如有想看小编思路的,可以点击左侧任务中的“不会了怎么办”
* 小编还是希望大家独立完成哦~
*/
int sum, feb;
if(year % 400 = 0 || (year % 100 !=0 && year % 4 ==0))
feb = 29;
else
feb = 28;
switch(month)
{
case 1:sum = 0;break;
case 2:sum = 31;break;
case 3:sum = 31 + feb;break;
case 4:sum = 62 + feb;break;
case 5:sum = 92 + feb;break;
case 6:sum = 123 + feb;break;
case 7:sum = 153 + feb;break;
case 8:sum = 184 + feb;break;
case 9:sum = 225 + feb;break;
case 10:sum = 255 + feb;break;
case 11:sum = 286 + feb;break;
case 12:sum = 316 + feb;break;
default:printf("一年当中只有12个月");break;
}
sum += day;
printf("%d年的%d月%d日是该年的第%d天\n",year,month,day,sum);
return 0;
}
可以的,不过你if(year%400==0.....)少写了一个“=”,改过来就对了