我按照视频中的在index.jsp中写了一个超链接，href="timer"，然后写了TimerAction，重写了execute方法，最后在struts.xml中配置了，但是跳转到success.jsp页面的时候报了404错误并且控制台没有报错信息，我该怎么追踪呢？
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> </head> <body> index，<a href="timer">执行action并计算执行时间</a> </body> </html>
package com.v3.action;
import com.opensymphony.xwork2.ActionSupport;
public class TimerAction extends ActionSupport {
@Override
public String execute() throws Exception {
for(int i=0; i < 10000; i++){
System.out.println("I LOVE V3");
}
return SUCCESS;
}
}<?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.5//EN" "http://struts.apache.org/dtds/struts-2.5.dtd"> <struts> <package name="default" namespace="/" extends="struts-default"> <action name="timer" class="com.v3.action.TimerAction"> <result>/success.jsp</result> </action> </package> </struts>
朋友 你的问题解决了吗?
<result>/success.jsp</result> 改成
<result name=“success”>/success.jsp</result> 试试呢0.0