个回答

• zmc1903150733

  2016-03-14 17:39:07

  搞不明白你为什么用 char来定义result，char应该是来定义字符的吧，比如char result='a';这里就算用也该是int吧

  
  

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• qq_小科比_0

  2016-03-06 14:59:35

  #include<stdio.h>

  int main()

  {

      int x,y;

      x=10;

      y=-3;

       printf("x+y=%d\n",x+y);   //printf  是输出  输出“”里面的

       printf("x-y=%d\n",x-y);

       printf("x*y=%d\n",x*y);

       printf("x/y=%d\n",x/y);

       printf("x%y=%d\n",x%y);

  return 0;

  }

  
  

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• 赵怀东

  2016-02-24 18:46:18

  #include<stdio.h>

  int main()

  {

      int x,y;

      x=10;

      y=-3;

       printf("x+y=%d\n",x+y);   //后边取得地址是运算的式子，因为在输出里计算的结果存在这里了

       printf("x-y=%d\n",x-y);

       printf("x*y=%d\n",x*y);

       printf("x/y=%d\n",x/y);

       printf("x%y=%d\n",x%y);

  return 0;

  }

  
  

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• S_herry

  2016-02-17 13:17:04

  #include <stdio.h>
  int main()
  {
      int x,y;
      x = 10;
      y = -3;
      printf("x+y=%d\n",x+y); 
      printf("x-y=%d\n",x-y);
      printf("x*y=%d\n",x*y);
      printf("x/y=%d\n",x/y);
      printf("x%y=%d\n",x%y); 
      return 0;   
  }

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• 慕仰3800911

  2016-02-17 13:16:43

  #include<stdio.h>

  int main()

  {

      int x,y;

      x=10;

      y=-3;

       printf("x+y=%d\n",x+y);

       printf("x-y=%d\n",x-y);

       printf("x*y=%d\n",x*y);

       printf("x/y=%d\n",x/y);

       printf("x%y=%d\n",x%y);

  return 0;

  }

  
  

  
  

  
  

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• ACDC

  2016-02-17 13:07:35

   int z =( x*8)/(y+2);

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