#include <stdio.h>
int main()
{
int year = 2008;
int month = 8;
int day = 8;
switch(month-1)
{
case 12:day+=31;
case 11:day+=30;
case 10:day+=31;
case 9:day+=30;
case 8:day+=31;
case 7:day+=31;
case 6:day+=30;
case 5:day+=31;
case 4:day+=30;
case 3:day+=31;
case 2:if((year%4==0 && year%100!=0) || year%400==0)
day+=29;
else
day+=28;
case 1:day+=31;
}
printf("2008年8月8日是该年的第%d天",day);
return 0;
}
首先,不加break会顺序执行接下来的代码,再有就是,假设,今天是8月8号,8月其实只过了8天,前面七个月是真正过完了的......