请问下！！

提示错误信息

org.apache.jasper.JasperException: /dologin.jsp (line: 2, column: 60) The JSP specification requires that an attribute name is preceded by whitespace

代码

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>

<jsp:useBean id="loginUser" class="com.po.Users"scope="page"></jsp:useBean>

<jsp:useBean id="userDAO" class="com.dao.UsersDAO"scope="page"></jsp:useBean>

<jsp:setProperty property="*" name="loginUser"/>

<%

request.setCharacterEncoding("utf-8");

 %>

<%

String path = request.getContextPath();

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";

if(userDAO.usersLogin(loginUser)){

session.setAttribute("loginUser", loginUser.getUsername());

request.getRequestDispatcher("login_success.jsp").forward(request, response);

}else{

response.sendRedirect("login_fail.jsp");

}

%>

包：com.dao

文件：UsersDAO.java

package com.dao;

import com.po.Users;

//业务逻辑类

public class UsersDAO {

//用户登录方法

public boolean usersLogin(Users u)

{

if ("admin".equals(u.getUsername())&&"admin"

.equals(u.getPassword())) 

{

return true;

}

else

{

return false;

}

}

}

包：com.po

文件：Users.java

package com.po;

//用户类

public class Users {

private String username;

private String password;

public Users()

{

}

public String getUsername() {

return username;

}

public void setUsername(String username) {

this.username = username;

}

public String getPassword() {

return password;

}

public void setPassword(String password) {

this.password = password;

}

}

我想问下 我哪错了？？？？？？？？