今天碰到一个关于exists很奇怪的问题
第一个语句如下:
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SELECT count (1) FROM APPLY t WHERE EXISTS ( SELECT r.APPLY_ID FROM RECORD r WHERE t.APPLY_ID = r.APPLY_ID ); |
产生的结果是:89584
第二个语句如下:
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SELECT count (1) FROM APPLY t WHERE EXISTS ( SELECT max (r.FINISH_TIME) FROM RECORD r WHERE t.APPLY_ID = r.APPLY_ID ); |
产生的结果是:432382
确实相当奇怪,对于exist子句来说,其判断的是子查询的值是否存在,也就是说,列名,和对列名求最大值没什么区别啊。
包括MySQL官方文档中也提到
Traditionally, an EXISTS subquery starts with SELECT *, but it could begin with SELECT 5 or SELECT column1 or anything at all. MySQL ignores the SELECT list in such a subquery, so it makes no difference.
大意就是MySQL会自动忽略到SELECT的列表。
后来在自己的环境测试了一下,确实是MySQL的一个bug
测试环境:MySQL 5.6.31,5.7.14
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mysql> create table t3(id int ,t datetime); Query OK, 0 rows affected (0.44 sec) mysql> insert into t3 values (1, '20160812' ); Query OK, 1 row affected (0.16 sec) mysql> select 1 from dual where exists ( select id from t3 where id=2); Empty set (0.15 sec) mysql> select 1 from dual where exists ( select max (id) from t3 where id=2); + ---+ | 1 | + ---+ | 1 | |
很明显,id等于2的列不存在,但是第二条语句还是当做TRUE来处理了。
也确认了下两条语句的执行计划和改写后的SQL
第一个语句
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mysql> EXPLAIN EXTENDED select 1 from dual where exists ( select id from t3 where id=2); + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+------------------+ | id | select_type | table | partitions | type | possible_keys | key | key_len | ref | rows | filtered | Extra | + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+------------------+ | 1 | PRIMARY | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | Impossible WHERE | | 2 | SUBQUERY | t3 | NULL | ALL | NULL | NULL | NULL | NULL | 1 | 100.00 | Using where | + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+------------------+ 2 rows in set , 2 warnings (0.00 sec) mysql> show warnings; + ---------+------+-------------------------------------------------------------------+ | Level | Code | Message | + ---------+------+-------------------------------------------------------------------+ | Warning | 1681 | 'EXTENDED' is deprecated and will be removed in a future release. | | Note | 1003 | /* select #1 */ select 1 AS `1` from DUAL where 0 | + ---------+------+-------------------------------------------------------------------+ |
第二个语句
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mysql> EXPLAIN EXTENDED select 1 from dual where exists ( select max (id) from t3 where id=2); + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+----------------+ | id | select_type | table | partitions | type | possible_keys | key | key_len | ref | rows | filtered | Extra | + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+----------------+ | 1 | PRIMARY | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | No tables used | | 2 | SUBQUERY | t3 | NULL | ALL | NULL | NULL | NULL | NULL | 1 | 100.00 | Using where | + ----+-------------+-------+------------+------+---------------+------+---------+------+------+----------+----------------+ 2 rows in set , 2 warnings (0.00 sec) mysql> show warnings; + ---------+------+-------------------------------------------------------------------+ | Level | Code | Message | + ---------+------+-------------------------------------------------------------------+ | Warning | 1681 | 'EXTENDED' is deprecated and will be removed in a future release. | | Note | 1003 | /* select #1 */ select 1 AS `1` from DUAL where 1 | + ---------+------+-------------------------------------------------------------------+ 2 rows in set (0.00 sec) |
执行计划及改写后的SQL确实有所不同,看来,确实是MySQL的一个bug了。
于是,给官方提了个bug
http://bugs.mysql.com/bug.php?id=82562
总结
建议写exists语句时,子查询中直接用*,而不用对列进行任何函数操作,避免碰到官方bug,
事实上,对于abs,floor函数又没问题
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mysql> select 1 from dual where exists ( select abs (id) from t3 where id=2); Empty set (0.07 sec) mysql> select 1 from dual where exists ( select floor(id) from t3 where id=2); Empty set (0.00 sec) |
以上所述是小编给大家介绍的MySQL关于exists的一个bug ,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持!