对文件中出现的单词排序次数

         

package FileRead;import javax.persistence.criteria.CriteriaBuilder;import java.io.FileInputStream;import java.io.FileNotFoundException;import java.util.*;class name{    String name=new String();    int num=0;}public class FileRead {    public static void main(String[] args) {        try {            FileInputStream fs=new FileInputStream("E:\\1.txt");            Scanner sc= new Scanner(fs);            int num=0;            HashMap<String,Integer> ts=new HashMap<String, Integer>();            LinkedList<name> list =new LinkedList<name>();            while (sc.hasNext()){                String s=sc.next();                if(ts.containsKey(s)){                    Integer i=ts.get(s)+1;                    ts.put(s,i);                }                else {                    ts.put(s,1);                }                num++;            }            System.out.println("开始排序.....");            int i=0;            int [] nums=new int[num];            Set<String> keys=ts.keySet();            for(String key:keys){                nums[i]=ts.get(key);                name n1=new name();                n1.num=nums[i];                n1.name=key;                list.add(n1);            }           Collections.sort(list, new Comparator<name>() {               @Override               public int compare(name o1, name o2) {                   if(o1.num<o2.num){                       return 1;                   }                   else if(o1.num==o2.num){                       return 0;                   }                   return -1;               }           });            for(name n1:list){                System.out.println(n1.num+":"+n1.name);            }        } catch (FileNotFoundException e) {            e.printStackTrace();        }    }}

整体思想就是先把文件中的数据全部读出来后，存入一个map中。然后对已经存在的他的出现次数+1,然后接着put进去map中。 最后创建一个链表，里面存储name对象。然后对list进行排序，根据Collections.sort(list,new Coparator<name>(){

    public int compare(name n1,name n2){

        if(n1.num<n2.num){

            return 1;        

        }else(n1.num==n2.num){

            return 0;    

        }

        return -1;

    }

})