原语句如下:
1 declare @d datetime 2 set @d=getdate() 3 SELECT [P_ID] FROM [ProductInfo] 4 WHERE [P_ID] IN 5 (28674,28667,28241,355,7210,14646,2164,11891,4519,14671,21788,21816,21817,21108,21196) 6 select [语句执行花费时间(毫秒)]=datediff(ms,@d,getdate())
现要求按括号中的ID顺序输出结果
此时, 可以用到SQLSERVER2000 以上版本中特有的表变量(table)(亦可用临时表,但性能还是有不小的差距)
结果语句如下:
1 declare @d2 datetime
2 set @d2=getdate()
3 declare @list Nvarchar(4000)
4 declare @str Nvarchar(10)
5 declare @orderid int
6 declare @tmp int
7
8 Declare @TableVar Table (OrderID int Primary Key ,TestID int)
9
10 set @list='28674,28667,28241,355,7210,14646,2164,11891,4519,14671,21788,21816,21817,21108,21196'
11 set @orderid=0
12 while (charindex(',',@list)>0)
13 begin
14
15 set @str=substring(@list,1,charindex(',',@list))
16 print @str
17 set @tmp= cast(Replace(@str,',','') as int)
18 print @tmp
19 set @list=substring(@list,len(@str)+1,len(@list)-len(@str)+1)
20 ----set @str=Replace(@str,',','')
21 set @orderid=@orderid+1
22 print @orderid
23 Insert Into @TableVar Values (@orderid, @tmp)
24 end
25
26 -- Select TestID From @TableVar order by OrderID
27
28
29 select [P_ID] from productinfo p
30 inner join @TableVar a
31 on p.p_ID=a.TestID
32 order by a.OrderID
33
34 select [语句执行花费时间(毫秒)]=datediff(ms,@d2,getdate())
随时随地看视频