shell脚本 怎么获取xml内容的标签属性值？

Question

<?xml version="1.0" encoding="UTF-8"?><api xmlns="http://ws.apache.org/ns/synapse" name="provider--appa" context="/apraa" version="1.0.0" version-type="url">
<resource methods="DELETE POST PUT GET" url-mapping="/*">
......
我想获取api标签内的name的值和context的值和version的值，赋给变量，后面要用的。

Answer 1

a=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "name=" |awk -F= '{print $2}'`;echo $ab=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "context=" |awk -F= '{print $2}'`;echo $bc=`awk '{for(i=1;i<=NF;i++)printf $i"\n";printf "\n"}' aa | grep "version=" |awk -F= '{print $2}'`;echo $c这里有两个version

Answer 2

1sed&nbsp;-nr&nbsp;'/task&nbsp;id/{s/.*<task&nbsp;id="([^"]+)"\sbusiness="([^"]+)".*/\1,\2/;p}'&nbsp;test.xml或者：1awk&nbsp;'/task&nbsp;id/{split($0,a,"(=\")|(\"&nbsp;)");print&nbsp;a[2]","a[4]}'&nbsp;test.xml&nbsp;或者：1sed&nbsp;-n&nbsp;'/task&nbsp;id/{s/"//g;s/^&nbsp;*//;p}'&nbsp;test.xml&nbsp;|&nbsp;awk&nbsp;-F"[=&nbsp;]"&nbsp;'{print&nbsp;$3","$5}'